Staple Dietary Ingredients Secured | My Web Site Page 295 Chapter 03 Page 05

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The Sun became angrier than ever and determined to have done with the trouble at once by killing the boys. From the eastern wall of the room projected numerous sharp spikes of white shell. There were turquoise spikes in the southern, abalone in the western, and jet in the northern walls. The boys were each hurled against the first of these, but dropped to the floor unharmed; then against the second, the third, and the fourth, with a like result. On the floor near the walls sat four large mortars with heavy pestles in them. The boys were placed in each of these successively and pounded, as their father thought, into fragments, but out of this also they came unharmed.

Once in a generation, a Wallace may be found physically, mentally, and morally qualified to wander unscathed through the tropical wilds of America and of Asia, to form magnificent collections as he wanders, and withal to think out sagaciously the conclusions suggested by his collections; but, to the ordinary explorer or collector, the dense forests of equatorial Asia and Africa, which constitute the favorite habitation of the Orang, the Chimpanzee, and the Gorilla, present difficulties of no ordinary magnitude; and the man who risks his life by even a short visit to the malarious shores of those regions may well be excused if he shrinks from facing the dangers of the interior; if he contents himself with stimulating the industry of the better-seasoned natives, and collecting and collating the more or less mythical reports and traditions with which they are too ready to supply him.

To find the weight of metal in a given substance:--_Multiply the standard by the number of c.c. used and divide by 100._ For example: a piece of zinc was dissolved and the gas evolved measured 73.9 c.c. Then by the rule, 0.2955×73.9/100 should give the weight of the piece of zinc. This gives 0.2184 gram. To find the percentage of metal in a given substance:--_Multiply the standard by the number of c.c. used and divide by the weight of substance taken._ For example: if 2 grams of a mineral were taken, and if on titrating with the permanganate solution (standard 1.008) 60.4 c.c. were required, then (1.008×60.4)/2 = 30.44. This is the percentage. If the standard is exactly 1 gram, and 1 gram of ore is always taken, these calculations become very simple. The "c.c." used give at once the percentage, or divided by 100 give the weight of metal. If it is desired to have a solution with a standard exactly 1.0 gram, it is best first to make one rather stronger than this, and then to standardise carefully. Divide 1000 by the standard thus obtained and the result will be the number of c.c. which must be taken and be diluted with water to 1 litre. For example: suppose the standard is 1.008, then 1000/1.008 gives 992, and if 992 c.c. be taken and diluted with water to 1000 c.c. a solution of the desired strength will be obtained. The standard of this should be confirmed. A simpler calculation for the same purpose is to multiply the standard by 1000; this will give the number of c.c. to which 1 litre of the solution should be diluted. In the above example a litre should be diluted to 1008 c.c.

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